Area of an Irregular Quadrilateral Calculator - Areavolumecalculator.com

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024

Area of an Irregular Quadrilateral diagonal (e) = 8 cm, diagonal(f) = 33 ft and diagonal = 1 is 140.4346279 cm² or 0.1511626 ft².

Area of an Irregular Quadrilateral diagonal (e) = 8 cm, diagonal(f) = 33 ft and diagonal = 1 in other units

Steps:

Given that Irregular Quadrilateral diagonal (e) = 8 cm, diagonal(f) = 33 ft and radians = 1

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

Unit Conversion of Width 33 ft = 1005.84 cm

To convert Foot to Centimeters

we know that, 1 Foot = 30.480 Centimeters

To convert Foot to Centimeters, multiply the foot value by 30.480

Result in Centimeters: 33 ft × 30.480 × cm/ft

Cancel The Comman factor of ft

Result in Centimeters: (33 x 30.480 cm)

Multiply 33 into 30.480

Result in Centimeters: 1005.84 Centimeters

∴ 33 Foot = 1005.84 Centimeters

A = 8 * 1005.84 * sin(1⁰)

Simplify the above equation

A = 140.4346279 cm²

∴ Area of an Irregular Quadrilateral diagonal (e) = 8 cm, diagonal(f) = 33 ft and degrees = 1 is 140.4346279 cm²

Unit Conversion of Length 8 cm = 0.2624672 ft

To convert Centimeters to Feet

we know that, 1 Centimeter = 0.032809 Feet or
1 Centimeter = 1/30.48 Feet

To convert Centimeters to Foot, multiply the centimeter value by 30.84.

Result in Foot: 8 × cm/30.84 × ft/cm

Cancel The Comman factor of cm

Result in Foot: 8/30.84 ft

DIvide the 8 by 30.84

Result in Feet: 0.2624672 feet

∴ 8 Centimeters = 0.2624672 foot

A = 0.2624672 ft * ft ft * sin(1⁰)

Simplify the above equation

Area = 0.1511626 degrees²

∴ Area of an Irregular Quadrilateral diagonal (e) = 8 cm, diagonal (f) = 33 ft with diagonal = 1 is [140.4346279, 0.1511626] cm²