Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 70 ft, diagonal(f) = 14 ft and degrees = 2.5 is 586.5027012 ft2

Area of an Irregular Quadrilateral diagonal (e) = 70 ft, diagonal(f) = 14 ft and degrees = 2.5 is 586.5027012 ft2


  Area of an Irregular Quadrilateral diagonal (e) = 70 ft, diagonal(f) = 14 ft and degrees = 2.5 in other units

Value unit
0.178766 km²
0.1110803 mi²
178.7660233
586.5027012 ft²
7038.0324144 in²
195.5009004 yd²
17876.6023326 cm²
178766.0233258 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 70 ft, diagonal(f) = 14 ft and radians = 2.5

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

A = 70 * 14 * sin(2.5)

Simplify the above equation

A = 586.5027012 ft²

∴ Area of an Irregular Quadrilateral diagonal (e) = 70 ft, diagonal(f) = 14 ft and degrees = 2.5 is 586.5027012 ft²