Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 64 in, diagonal(f) = 40 m and diagonal = 48 is 74899.4861544 in2 or 48.3222491 m2.

Area of an Irregular Quadrilateral diagonal (e) = 64 in, diagonal(f) = 40 m and diagonal = 48 is 74899.4861544 in2 or 48.3222491 m2.


  Area of an Irregular Quadrilateral diagonal (e) = 64 in, diagonal(f) = 40 m and diagonal = 48 in other units

Value unit
1.9024469 km²
1.1821287 mi²
1902.4469483
6241.6238462 ft²
74899.4861544 in²
2080.5412821 yd²
190244.6948322 cm²
1902446.9483218 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 64 in, diagonal(f) = 40 m and radians = 48

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

      Unit Conversion of Width 40 m = 1574.8 in

40 meter is 1574.8 inches

To convert Meters to Inches

we know that, 1 Meter = 39.37 Inch

To convert meter to Inch,multiply the meter value by 39.37.

Result in Inches: 40 m × 39.37 × in/m

Cancel The Comman factor of m

Result in Inches: (40 * 39.37 in)

Multiply 1574.8 into 39.37

∴ 40 meter = 1574.8 inches

A = 64 * 1574.8 * sin(480)

Simplify the above equation

A = 74899.4861544 in²

∴ Area of an Irregular Quadrilateral diagonal (e) = 64 in, diagonal(f) = 40 m and degrees = 48 is 74899.4861544 in²

or

      Unit Conversion of Length 64 in = 1.6256 m

64 inches is 1.6256 meters

To convert inches to meter

we know that, 1 inch = 0.0254 meters

To convert inches to meter,multiply the inches value by 0.0254.

Result in Inches: 64 in x 0.0254 × m/in

Cancel The Comman factor of m

Result in Meters: (64 x 0.0254 m)

Multiply 64 into 0.0254

Result in meters: 1.6256 meters

∴ 64 inches = 1.6256 meters

A = 1.6256 m * m m * sin(480)

Simplify the above equation

Area = 48.3222491 degrees²

∴ Area of an Irregular Quadrilateral diagonal (e) = 64 in, diagonal (f) = 40 m with diagonal = 48 is [74899.4861544, 48.3222491] in²