Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 6 ft, diagonal(f) = 75 cm and radians = 1.4 is 14.5489624 ft2 or 13516.4284965 cm2.

Area of an Irregular Quadrilateral diagonal (e) = 6 ft, diagonal(f) = 75 cm and radians = 1.4 is 14.5489624 ft2 or 13516.4284965 cm2.


  Area of an Irregular Quadrilateral diagonal (e) = 6 ft, diagonal(f) = 75 cm and radians = 1.4 in other units

Value unit
0.0044345 km²
0.0027555 mi²
4.4345237
14.5489624 ft²
174.5875488 in²
4.8496541 yd²
443.452374 cm²
4434.5237395 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 6 ft, diagonal(f) = 75 cm and radians = 1.4

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

      Unit Conversion of Width 75 cm = 2.4606299 ft

75 Centimeters is 2.4606299 foot

To convert Centimeters to Feet

we know that, 1 Centimeter = 0.032809 Feet or
                         1 Centimeter = 1/30.48 Feet

To convert Centimeters to Foot, multiply the centimeter value by 30.84.

Result in Foot: 75 × cm/30.84 × ft/cm

Cancel The Comman factor of cm

Result in Foot: 75/30.84 ft

DIvide the 75 by 30.84

Result in Feet: 2.4606299 feet

∴ 75 Centimeters = 2.4606299 foot

A = 6 * 2.4606299 * sin(1.4)

Simplify the above equation

A = 14.5489624 ft²

∴ Area of an Irregular Quadrilateral diagonal (e) = 6 ft, diagonal(f) = 75 cm and radians = 1.4 is 14.5489624 ft²

or

      Unit Conversion of Length 6 ft = 182.88 cm

6 Foot is 182.88 Centimeters

To convert Foot to Centimeters

we know that, 1 Foot = 30.480 Centimeters

To convert Foot to Centimeters, multiply the foot value by 30.480

Result in Centimeters: 6 ft × 30.480 × cm/ft

Cancel The Comman factor of ft

Result in Centimeters: (6 x 30.480 cm)

Multiply 6 into 30.480

Result in Centimeters: 182.88 Centimeters

∴ 6 Foot = 182.88 Centimeters

A = 182.88 cm * 75 cm * sin(1.4)

Simplify the above equation

Area = 13516.4284965 cm²

∴ Area of an Irregular Quadrilateral diagonal (e) = 6 ft, diagonal (f) = 75 cm and radians = 1.4 is 13516.4284965 ft²