Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 57 cm, diagonal(f) = 59 in and diagonal = 31 is 4399.4655366 cm2 or 681.9185226 in2.

Area of an Irregular Quadrilateral diagonal (e) = 57 cm, diagonal(f) = 59 in and diagonal = 31 is 4399.4655366 cm2 or 681.9185226 in2.


  Area of an Irregular Quadrilateral diagonal (e) = 57 cm, diagonal(f) = 59 in and diagonal = 31 in other units

Value unit
0.0439947 km²
0.0273371 mi²
43.9946554
144.3394205 ft²
1732.0730459 in²
48.1131402 yd²
4399.4655366 cm²
43994.655366 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 57 cm, diagonal(f) = 59 in and radians = 31

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

      Unit Conversion of Width 59 in = 149.86 cm

59 Inches is 149.86 Centimeters

To convert Inches to Centimeters

we know that, 1 Inche = 2.54 Centimeters

To convert Inches to Centimeters, multiply the inche value by 2.54

Result in Centimeters: 59 in × 2.54 × cm/in

Cancel The Comman factor of in

Result in Centimeters: (59 x 2.54 cm)

Multiply 59 into 2.54

Result in Centimeters: 149.86 Centimeters

∴ 59 Inches = 149.86 Centimeters

A = 57 * 149.86 * sin(310)

Simplify the above equation

A = 4399.4655366 cm²

∴ Area of an Irregular Quadrilateral diagonal (e) = 57 cm, diagonal(f) = 59 in and degrees = 31 is 4399.4655366 cm²

or

      Unit Conversion of Length 57 cm = 22.4409449 in

57 Centimeters is 22.4409449 inches

To convert Centimeter to Inches

we know that, 1 Centimeter = 0.393705 inches or
                         1 Centimeter = 1/2.54 inches

To convert Centimeters to inches, divide the centimeter value by 2.54.

Result in Centimeters: 57 × cm/2.54 × in/cm

Cancel The Comman factor of cm

Result in Inches: 57/2.54 in

Divide the 57 by 2.54

Result in Inches: 22.4409449 inches

∴ 57 Centimeters = 22.4409449 inches

A = 22.4409449 in * in in * sin(310)

Simplify the above equation

Area = 681.9185226 degrees²

∴ Area of an Irregular Quadrilateral diagonal (e) = 57 cm, diagonal (f) = 59 in with diagonal = 31 is [4399.4655366, 681.9185226] cm²