Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 5 cm, diagonal(f) = 33 ft and diagonal = 67 is 4629.403009 cm2 or 4.9830481 ft2.

Area of an Irregular Quadrilateral diagonal (e) = 5 cm, diagonal(f) = 33 ft and diagonal = 67 is 4629.403009 cm2 or 4.9830481 ft2.


  Area of an Irregular Quadrilateral diagonal (e) = 5 cm, diagonal(f) = 33 ft and diagonal = 67 in other units

Value unit
0.046294 km²
0.0287658 mi²
46.2940301
151.8833008 ft²
1822.5996098 in²
50.6277669 yd²
4629.403009 cm²
46294.03009 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 5 cm, diagonal(f) = 33 ft and radians = 67

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

      Unit Conversion of Width 33 ft = 1005.84 cm

33 Foot is 1005.84 Centimeters

To convert Foot to Centimeters

we know that, 1 Foot = 30.480 Centimeters

To convert Foot to Centimeters, multiply the foot value by 30.480

Result in Centimeters: 33 ft × 30.480 × cm/ft

Cancel The Comman factor of ft

Result in Centimeters: (33 x 30.480 cm)

Multiply 33 into 30.480

Result in Centimeters: 1005.84 Centimeters

∴ 33 Foot = 1005.84 Centimeters

A = 5 * 1005.84 * sin(670)

Simplify the above equation

A = 4629.403009 cm²

∴ Area of an Irregular Quadrilateral diagonal (e) = 5 cm, diagonal(f) = 33 ft and degrees = 67 is 4629.403009 cm²

or

      Unit Conversion of Length 5 cm = 0.164042 ft

5 Centimeters is 0.164042 foot

To convert Centimeters to Feet

we know that, 1 Centimeter = 0.032809 Feet or
                         1 Centimeter = 1/30.48 Feet

To convert Centimeters to Foot, multiply the centimeter value by 30.84.

Result in Foot: 5 × cm/30.84 × ft/cm

Cancel The Comman factor of cm

Result in Foot: 5/30.84 ft

DIvide the 5 by 30.84

Result in Feet: 0.164042 feet

∴ 5 Centimeters = 0.164042 foot

A = 0.164042 ft * ft ft * sin(670)

Simplify the above equation

Area = 4.9830481 degrees²

∴ Area of an Irregular Quadrilateral diagonal (e) = 5 cm, diagonal (f) = 33 ft with diagonal = 67 is [4629.403009, 4.9830481] cm²