Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 34 in, diagonal(f) = 15 m and radians = 2.4 is 13562.4225633 in2 or 8.74995 m2.

Area of an Irregular Quadrilateral diagonal (e) = 34 in, diagonal(f) = 15 m and radians = 2.4 is 13562.4225633 in2 or 8.74995 m2.


  Area of an Irregular Quadrilateral diagonal (e) = 34 in, diagonal(f) = 15 m and radians = 2.4 in other units

Value unit
0.3444855 km²
0.2140539 mi²
344.4855331
1130.2018803 ft²
13562.4225633 in²
376.7339601 yd²
34448.5533108 cm²
344485.5331078 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 34 in, diagonal(f) = 15 m and radians = 2.4

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

      Unit Conversion of Width 15 m = 590.55 in

15 meter is 590.55 inches

To convert Meters to Inches

we know that, 1 Meter = 39.37 Inch

To convert meter to Inch,multiply the meter value by 39.37.

Result in Inches: 15 m × 39.37 × in/m

Cancel The Comman factor of m

Result in Inches: (15 * 39.37 in)

Multiply 590.55 into 39.37

∴ 15 meter = 590.55 inches

A = 34 * 590.55 * sin(2.4)

Simplify the above equation

A = 13562.4225633 in²

∴ Area of an Irregular Quadrilateral diagonal (e) = 34 in, diagonal(f) = 15 m and radians = 2.4 is 13562.4225633 in²

or

      Unit Conversion of Length 34 in = 0.8636 m

34 inches is 0.8636 meters

To convert inches to meter

we know that, 1 inch = 0.0254 meters

To convert inches to meter,multiply the inches value by 0.0254.

Result in Inches: 34 in x 0.0254 × m/in

Cancel The Comman factor of m

Result in Meters: (34 x 0.0254 m)

Multiply 34 into 0.0254

Result in meters: 0.8636 meters

∴ 34 inches = 0.8636 meters

A = 0.8636 m * 15 m * sin(2.4)

Simplify the above equation

Area = 8.74995 m²

∴ Area of an Irregular Quadrilateral diagonal (e) = 34 in, diagonal (f) = 15 m and radians = 2.4 is 8.74995 in²