Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : Jan 03, 2024


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Diagonal (e)
Diagonal (f)
Angle α


Area of an Irregular Quadrilateral diagonal (e) = 33 yd, diagonal(f) = 85 yd and degrees = 1 is 48.9540001 yd2

Area of an Irregular Quadrilateral diagonal (e) = 33 yd, diagonal(f) = 85 yd and degrees = 1 is 48.9540001 yd2


  Area of an Irregular Quadrilateral diagonal (e) = 33 yd, diagonal(f) = 85 yd and degrees = 1 in other units

Value unit
0.0447635 km²
0.0278148 mi²
44.7635377
146.8620003 ft²
1762.3440036 in²
48.9540001 yd²
4476.3537691 cm²
44763.5376914 mm²

Steps:

Given that Irregular Quadrilateral diagonal (e) = 33 yd, diagonal(f) = 85 yd and radians = 1

We know that, Area = e * f * sin(α)

Put the values of e, f and α in above Area Formula

A = 33 * 85 * sin(10 )

Simplify the above equation

A = 48.9540001 yd²

∴ Area of an Irregular Quadrilateral diagonal (e) = 33 yd, diagonal(f) = 85 yd and degrees = 1 is 48.9540001 yd²