Area of an Irregular Quadrilateral Calculator
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Area of an Irregular Quadrilateral diagonal (e) = 3 ft, diagonal(f) = 3 in and diagonal = 133 is 0.5485153 ft2 or 78.9861998 in2.
Area of an Irregular Quadrilateral diagonal (e) = 3 ft, diagonal(f) = 3 in and diagonal = 133 is 0.5485153 ft2 or 78.9861998 in2.
Area of an Irregular Quadrilateral diagonal (e) = 3 ft, diagonal(f) = 3 in and diagonal = 133 in other units
| Value | unit |
|---|---|
| 0.0001672 | km² |
| 0.0001039 | mi² |
| 0.1671875 | m² |
| 0.5485153 | ft² |
| 6.5821836 | in² |
| 0.1828384 | yd² |
| 16.7187463 | cm² |
| 167.1874634 | mm² |
Steps:
Given that Irregular Quadrilateral diagonal (e) = 3 ft, diagonal(f) = 3 in and radians = 133
We know that, Area = e * f * sin(α)
Put the values of e, f and α in above Area Formula
Unit Conversion of Width 3 in = 0.25 ft
3 Inches is 0.25 feet
To convert Inches to Feet
we know that, 1 Inches = 0.0833333 Feet or
1 Foot = 1/12 foot
To convert Inches to Feet, divide the inche value by 12.
Result in Foot: 3 × in/12 × ft/in
Cancel The Comman factor of in
Result in Feet: $3\above 1pt12$
Divide the 3 by 12
Result in Feet: 0.25 feet
∴ 3 Inches = 0.25 feet
A = 3 * 0.25 * sin(1330)
Simplify the above equation
A = 0.5485153 ft²
∴ Area of an Irregular Quadrilateral diagonal (e) = 3 ft, diagonal(f) = 3 in and degrees = 133 is 0.5485153 ft²
or
Unit Conversion of Length 3 ft = 36.0 in
3 Foot is 36.0 inches
To convert Foot to Inches
we know that, 1 Foot = 12 inches
To convert Foot to inches, multiply the foot value by 12.
Result in Foot: 3 ft × 12 × in/ft
Cancel The Comman factor of ft
Result in Inches: (3 x 12 in)
Multiply 3 into 12
Result in Inches: 36.0 inches
∴ 3 Foot = 36.0 inches
A = 36.0 in * in in * sin(1330)
Simplify the above equation
Area = 78.9861998 degrees²
∴ Area of an Irregular Quadrilateral diagonal (e) = 3 ft, diagonal (f) = 3 in with diagonal = 133 is [0.5485153, 78.9861998] ft²