Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Angle (β)

Enter the Base (a)

Enter the Angle (γ)


Area of Triangle angle (β) 40 degrees, side 41 centimeters and with angle (γ) 124 degrees is 1617.2879852 centimeters².

The area of a triangle is defined as the total space that is enclosed by any particular triangle. The basic formula to find the area of a given triangle is A = a² * sin(β) * sin(γ)/(2 * sin(β + γ)), where a is side, sin(β), sin(γ) are the angles of the given triangle. Area of Triangle angle (β) 40 degrees, side 41 centimeters and with angle (γ) 124 degrees is 1617.2879852 centimeters².


    Area of a Triangle Angle(β) = 40 degrees by side(a) = 41 cm with angle(γ) = 124 degrees in other units

Value unit
0.0161729 km2
0.0100494 mi2
16.1728799 m2
53.0606294 ft2
636.7275532 in2
17.6868765 yd2
1617.2879852 cm2
16172.879852 mm2

Steps:

Given that Angle (β) = 40 degrees , Side (a) = 41 cm and with Angle(γ) = 124 degrees

We Know that, Area = a² * sin(β) * sin(γ)/(2 * sin(β + γ))

Substitute the values of the angle (β) = 40 degrees , the side (a) = 41 cm , and the with angle (γ) = 124 degrees into the formula

41² * sin(cm) * sin(40)/(2 * sin(degrees + 124))

Simplify the above equations

A = 1617.2879852 cm²

∴ Area of a Triangle angle (β) 40 degrees , side (b) 41 cm and with angle (γ) = 124 degrees is 1617.2879852 cm²