Area of a Triangle Angle(β) = 17 degrees by side(a) = 27 in with angle(γ) = 48 degrees Calculator
Area of Triangle angle (β) 17 degrees, side 27 inches and with angle (γ) 48 degrees is 87.3307725 inches².
The area of a triangle is defined as the total space that is enclosed by any particular triangle. The basic formula to find the area of a given triangle is A = a² * sin(β) * sin(γ)/(2 * sin(β + γ)), where a is side, sin(β), sin(γ) are the angles of the given triangle. Area of Triangle angle (β) 17 degrees, side 27 inches and with angle (γ) 48 degrees is 87.3307725 inches².
Area of a Triangle Angle(β) = 17 degrees by side(a) = 27 in with angle(γ) = 48 degrees in other units
| Value | unit |
|---|---|
| 0.0022182 | km2 |
| 0.0013783 | mi2 |
| 2.2182016 | m2 |
| 7.2775644 | ft2 |
| 87.3307725 | in2 |
| 2.4258548 | yd2 |
| 221.8201621 | cm2 |
| 2218.2016215 | mm2 |
Steps:
Given that Angle (β) = 17 degrees , Side (a) = 27 in and with Angle(γ) = 48 degrees
We Know that, Area = a² * sin(β) * sin(γ)/(2 * sin(β + γ))
Substitute the values of the angle (β) = 17 degrees , the side (a) = 27 in , and the with angle (γ) = 48 degrees into the formula
27² * sin(in) * sin(17)/(2 * sin(degrees + 48))
Simplify the above equations
A = 87.3307725 in²
∴ Area of a Triangle angle (β) 17 degrees , side (b) 27 in and with angle (γ) = 48 degrees is 87.3307725 in²