Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (a)

Enter the Base (b)

Enter the Base (c)


Area of Triangle 11 meters, 65 meters and 67 meters is 355.7080088 meters.

The area of a triangle is defined as the total space that is enclosed by any particular triangle. The basic formula to find the area of a given triangle is A = 1/4 × √((a + b + c) x (-a + b + c) x (a - b + c) x (a + b - c)), where a,b,c are the bases of the given triangle. Area of Triangle 11 meters, 65 meters and 67 meters is 355.7080088 meters.


    Area of Triangle side (a) 11 m by side (b) 65 m by side (c) 67 m in other units

Value unit
0.355708 km2
0.2210273 mi2
355.7080088 m2
1167.0210262 ft2
14004.252315 in2
389.0070087 yd2
35570.80088 cm2
355708.0088 mm2

Steps:

Given that side (a) = 11 m and side (b) =65 m and side (c) = 67 m

Area = 1/4 √((a+b+c)*(-a+b+c)*(a-b+c)*(a+b-c))

Put the value of a,b and c value in Area Formula.

Area = 1/4 √((11 + 65 + 67)*(-11 + 65 + 67)*(11-65+67)*(11 + 65 - 67))

Simplify the above exception

Area = 355.7080088 m2

∴ Area of Triangle side (a) 11 m by side (b) 65 m by side (c) 67 m is 355.7080088 m2