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Area of a Rhombus Side (a) 48 ft With Angle(α) 65 Degrees is 2088.1331413 ft2
Area of a Rhombus Side (a) 48 ft With Angle(α) 65 Degrees is 2088.1331413 ft2
Area of a Rhombus Side (a) 48 ft With Angle(α) 65 Degrees in other units
| Value | unit |
|---|---|
| 0.636463 | km² |
| 0.3954807 | mi² |
| 636.4629815 | m² |
| 2088.1331413 | ft² |
| 25057.5976956 | in² |
| 696.0443804 | yd² |
| 63646.2981468 | cm² |
| 636462.9814682 | mm² |
Steps:
Given that Rhombus side (a) = 48 ft and with angle = 65 degrees
We know that, Area = a² * sin(α)
Put the values a and angle(α) values in above Area Formula
A = 48² * sin(650)
Simplify the above Equations
A = 2088.1331413 ft²
∴ Area of a Rhombus side (a) = 48 ft with angle(α) = 65 degrees is 2088.1331413 ft²