Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Choose

Diagonal (e)
Diagonal (f)


Area of a Rhombus Diagonal-e 9 in and Diagonal-f 65 ft is 3510.0 in2 or 24.375 ft2.

Area of a Rhombus Diagonal-e 9 in and Diagonal-f 65 ft is 3510.0 in2 or 24.375 ft2.


  Area of a Rhombus Diagonal-e 9 in and Diagonal-f 65 ft in other units

Value unit
0.089154 km²
0.0553979 mi²
89.154
292.5 ft²
3510.0 in²
97.5 yd²
8915.4 cm²
89154.0 mm²

Steps:

Given that Rhombus Diagonal (e) = 9 in and Diagonal (f) = 65 ft

We know that, Area = (e * f)/2

      Unit Conversion of Width 65 ft = 780.0 in

65 Foot is 780.0 inches

To convert Foot to Inches

we know that, 1 Foot = 12 inches

To convert Foot to inches, multiply the foot value by 12.

Result in Foot: 65 ft × 12 × in/ft

Cancel The Comman factor of ft

Result in Inches: (65 x 12 in)

Multiply 65 into 12

Result in Inches: 780.0 inches

∴ 65 Foot = 780.0 inches

Put the values e, f values in above Area Formula

A = (9 * 780.0)/2

Simplify the above Equations

A = 3510.0 in²

∴ Area of a Rhombus diagonal-e 9 in and diagonal-f 65 ft is 3510.0 in²

or

      Unit Conversion of Length 9 in = 0.75 ft

9 Inches is 0.75 feet

To convert Inches to Feet

we know that, 1 Inches = 0.0833333 Feet or
                         1 Foot = 1/12 foot

To convert Inches to Feet, divide the inche value by 12.

Result in Foot: 9 × in/12 × ft/in

Cancel The Comman factor of in

Result in Feet: $9\above 1pt12$

Divide the 9 by 12

Result in Feet: 0.75 feet

∴ 9 Inches = 0.75 feet

Put the values e, f values in above Area Formula

A = (0.75 * 65)/2

Simplify the above Equations

A = 24.375 ft²

∴ Area of a Rhombus diagonal-e 9 in and diagonal-f 65 ft is 24.375 ft²