Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Choose

Diagonal (e)
Diagonal (f)


Area of a Rhombus Diagonal-e 8 m and Diagonal-f 22 in is 2.2352 m2 or 3464.56 in2.

Area of a Rhombus Diagonal-e 8 m and Diagonal-f 22 in is 2.2352 m2 or 3464.56 in2.


  Area of a Rhombus Diagonal-e 8 m and Diagonal-f 22 in in other units

Value unit
0.0022352 km²
0.0013889 mi²
2.2352
7.3333333 ft²
88.0 in²
2.4444444 yd²
223.52 cm²
2235.2 mm²

Steps:

Given that Rhombus Diagonal (e) = 8 m and Diagonal (f) = 22 in

We know that, Area = (e * f)/2

      Unit Conversion of Width 22 in = 0.5588 m

22 inches is 0.5588 meters

To convert inches to meter

we know that, 1 inch = 0.0254 meters

To convert inches to meter,multiply the inches value by 0.0254.

Result in Inches: 22 in x 0.0254 × m/in

Cancel The Comman factor of m

Result in Meters: (22 x 0.0254 m)

Multiply 22 into 0.0254

Result in meters: 0.5588 meters

∴ 22 inches = 0.5588 meters

Put the values e, f values in above Area Formula

A = (8 * 0.5588)/2

Simplify the above Equations

A = 2.2352 m²

∴ Area of a Rhombus diagonal-e 8 m and diagonal-f 22 in is 2.2352 m²

or

      Unit Conversion of Length 8 m = 314.96 in

8 meter is 314.96 inches

To convert Meters to Inches

we know that, 1 Meter = 39.37 Inch

To convert meter to Inch,multiply the meter value by 39.37.

Result in Inches: 8 m × 39.37 × in/m

Cancel The Comman factor of m

Result in Inches: (8 * 39.37 in)

Multiply 314.96 into 39.37

∴ 8 meter = 314.96 inches

Put the values e, f values in above Area Formula

A = (314.96 * 22)/2

Simplify the above Equations

A = 3464.56 in²

∴ Area of a Rhombus diagonal-e 8 m and diagonal-f 22 in is 3464.56 in²