Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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Diagonal (e)
Diagonal (f)


Area of a Rhombus Diagonal-e 5 in and Diagonal-f 46 m is 4527.55 in2 or 2.921 m2.

Area of a Rhombus Diagonal-e 5 in and Diagonal-f 46 m is 4527.55 in2 or 2.921 m2.


  Area of a Rhombus Diagonal-e 5 in and Diagonal-f 46 m in other units

Value unit
0.1149998 km²
0.0714577 mi²
114.99977
377.2958333 ft²
4527.55 in²
125.7652778 yd²
11499.977 cm²
114999.77 mm²

Steps:

Given that Rhombus Diagonal (e) = 5 in and Diagonal (f) = 46 m

We know that, Area = (e * f)/2

      Unit Conversion of Width 46 m = 1811.02 in

46 meter is 1811.02 inches

To convert Meters to Inches

we know that, 1 Meter = 39.37 Inch

To convert meter to Inch,multiply the meter value by 39.37.

Result in Inches: 46 m × 39.37 × in/m

Cancel The Comman factor of m

Result in Inches: (46 * 39.37 in)

Multiply 1811.02 into 39.37

∴ 46 meter = 1811.02 inches

Put the values e, f values in above Area Formula

A = (5 * 1811.02)/2

Simplify the above Equations

A = 4527.55 in²

∴ Area of a Rhombus diagonal-e 5 in and diagonal-f 46 m is 4527.55 in²

or

      Unit Conversion of Length 5 in = 0.127 m

5 inches is 0.127 meters

To convert inches to meter

we know that, 1 inch = 0.0254 meters

To convert inches to meter,multiply the inches value by 0.0254.

Result in Inches: 5 in x 0.0254 × m/in

Cancel The Comman factor of m

Result in Meters: (5 x 0.0254 m)

Multiply 5 into 0.0254

Result in meters: 0.127 meters

∴ 5 inches = 0.127 meters

Put the values e, f values in above Area Formula

A = (0.127 * 46)/2

Simplify the above Equations

A = 2.921 m²

∴ Area of a Rhombus diagonal-e 5 in and diagonal-f 46 m is 2.921 m²