Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


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Regular Octagon Side


Area of a Regular Octagon side 5 yd is 120.7106781 yd²

Area of a Regular Octagon side 5 yd is 120.7106781 yd²


    Area of a Regular Octagon side 5 yd in other units

Value unit
0.1103778 km²
0.0685858 mi²
110.3778441
362.1320343 ft²
4345.5844116 in²
120.7106781 yd²
11037.7844055 cm²
110377.8440546 mm²

Steps:

Given that Side, a = 5 yd

We know that, Area = 2 (1 + √2) * a²

Put the value of side in area Formula.

A = 2 (1 + √2) * 5²

Simplify the above equation

A = 120.7106781 yd²

∴ Area of a Regular Octagon side 5 yd is 120.7106781 yd²