Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Radius(r)

Enter the Height(h)


Volume of a Cone radius 62 foot by 95 foot is 382221.7337357 foot3

The Volume of a Cone is equal to the area of the base π r2 times the height h/3 . If volume of a cone radius 62 foot by 95 foot is 382221.7337357 foot3.


    Volume of Cone 62 ft by 95 ft in other units

Value unit
116.5011844 km3
72.3906598 mi3
116501.1844426 m3
382221.7337357 ft3
4586660.8048284 in3
127407.2445786 yd3
11650118.4442641 cm3
116501184.4426414 mm3

Steps:

Volume of Cone π x radius2 x $height\above 1pt3$

Substitute the value of the radius r = 62.0 ft height h = 95.0 ft into the formula to find the volume. Pi (π) is approximately equal to 3.14 .

π x 622 ft2 x $95\above 1pt3$ ft

Raise 62 ft power of 2

π x 3844.0 ft2 x $95\above 1pt3$ ft

Divide 95 by 3

π x 3844.0 ft2 x 31.6666667 ft

Multiply 3844.0 ft2 and 31.6666667 ft

π x 121726.6667948 ft3

Combine π and 121726.6667948 ft3

The result can be shown in multiple forms.

Exact Form

Volume = 121726.6667948π ft3

∴ Volume of Cone radius 62 ft and height 95 ft is 121726.6667948π ft3

Decimal Form

Volume = 382221.7337357 ft3

∴ Volume of Cone radius 62 ft and height 95 ft is 382221.7337357 ft3