Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Radius(r)

Enter the Height(h)


Volume of a Cone radius 39 foot by 62 foot is 98702.7601592 foot3

The Volume of a Cone is equal to the area of the base π r2 times the height h/3 . If volume of a cone radius 39 foot by 62 foot is 98702.7601592 foot3.


    Volume of Cone 39 ft by 62 ft in other units

Value unit
30.0846013 km3
18.693751 mi3
30084.6012965 m3
98702.7601592 ft3
1184433.1219104 in3
32900.9200531 yd3
3008460.1296524 cm3
30084601.2965242 mm3

Steps:

Volume of Cone π x radius2 x $height\above 1pt3$

Substitute the value of the radius r = 39.0 ft height h = 62.0 ft into the formula to find the volume. Pi (π) is approximately equal to 3.14 .

π x 392 ft2 x $62\above 1pt3$ ft

Raise 39 ft power of 2

π x 1521.0 ft2 x $62\above 1pt3$ ft

Divide 62 by 3

π x 1521.0 ft2 x 20.6666667 ft

Multiply 1521.0 ft2 and 20.6666667 ft

π x 31434.0000507 ft3

Combine π and 31434.0000507 ft3

The result can be shown in multiple forms.

Exact Form

Volume = 31434.0000507π ft3

∴ Volume of Cone radius 39 ft and height 62 ft is 31434.0000507π ft3

Decimal Form

Volume = 98702.7601592 ft3

∴ Volume of Cone radius 39 ft and height 62 ft is 98702.7601592 ft3