Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the value of base radius(r)

Enter the Value of height(h)


If the cone Radius 5 inches by height 56 meters is 34692.6930135 inches2 or 22.3823825 meters2.


The surface area of a cone is equal to the area of the base plus the area of the cone. If the cone Radius 5 inches by height 56 meters is 34692.6930135 inches2 or 22.3823825 meters2.


    Surface Area of a Cone 5 in by 56 m in other units

Value unit
0.8811944 km2
0.5475502 mi2
881.1944025 m2
2891.0577511 ft2
34692.6930135 in2
963.685917 yd2
88119.4402543 cm2
881194.4025429 mm2

Steps:

Given that Base radius(r) = 5 in and height(h) = 56 m

Surface Area of a Cone = $(π⋅(Radius))$⋅($(Radius)$ + $\sqrt{(Radius)^2+(Height)^2}$)

Substitute the values of the radius r = 5 in and height h = 56 m into the formula. Pi (π) is approximately equal to 3.14 .

      Unit Conversion of 56 m = 2204.72 in

56 meter is 2204.72 inches

To convert Meters to Inches

we know that, 1 Meter = 39.37 Inch

To convert meter to Inch,multiply the meter value by 39.37.

Result in Inches: 56 m × 39.37 × in/m

Cancel The Comman factor of m

Result in Inches: (56 * 39.37 in)

Multiply 2204.72 into 39.37

∴ 56 meter = 2204.72 inches


$(π⋅(5))$⋅ $(5$ + $\sqrt{(5)^2 + (2204.72)^2})$ in

Move 5 to the left of π.

$(5π)$⋅$ (5$ + $\sqrt{(5)^2 + (2204.72)^2}$

Simplify each term

Raise 5 in to the power of 2 and 2204.72 to the power of 2

$(5π)$⋅$ (5$ + $\sqrt{(25.0) + (4860790.2784)}$ in

Add 25.0 in and 4860790.2784 in

$(5π)$ in⋅$ (5$ + $\sqrt{(4860815.2784)}$ in

Multipy 5π in and 5 in

25.0π in + (5π . $\sqrt{ 4860815.2784 }$) in


Put the value of $\sqrt{ 4860815.2784 }$ = 2204.7256696 in formula

25.0π in + (5π . 2204.7256696) in

Mulitply the 5π and 2204.7256696

25.0π in + (11023.6283482π)

Add 25.0π in and 11023.6283482π in

The result can be shown in multiple forms

Exact Form

Area = 11048.6283482π in

∴ Surface Area of Cone 5 in by 56 m is 11048.6283482π in2

Decimal Form

34692.6930135 in2

∴ Surface Area of Cylinder 5 in by 56 m is 34692.6930135 in2

or

      Unit Conversion of 5 in = 0.127 m

5 inches is 0.127 meters

To convert inches to meter

we know that, 1 inch = 0.0254 meters

To convert inches to meter,multiply the inches value by 0.0254.

Result in Inches: 5 in x 0.0254 × m/in

Cancel The Comman factor of m

Result in Meters: (5 x 0.0254 m)

Multiply 5 into 0.0254

Result in meters: 0.127 meters

∴ 5 inches = 0.127 meters


$(π⋅(0.127))$⋅ $(0.127$ + $\sqrt{(0.127)^2 + (56)^2})$ m

Move 0.127 to the left of π.

$(0.127π)$⋅$ (0.127$ + $\sqrt{(0.127)^2 + (56)^2}$

Simplify each term

Raise 0.127 m to the power of 2 and 56 to the power of 2

$(0.127π)$⋅$ (0.127$ + $\sqrt{(0.016129) + (3136.0)}$ m

Add 0.016129 m and 3136.0 m

$(0.127π)$ m ⋅ $ (0.127$ + $\sqrt{(3136.016129)}$ m

Multipy 0.127π m and 0.127 m

0.016129π m + (0.127π . $\sqrt{ 3136.016129 }$) m

Put the value of $\sqrt{3136.016129}$ = 56.000144 in formula

0.016129π m + (0.127π . 56.000144) m

Mulitply the 0.127π and 56.000144

0.016129π m + (7.1120183π)

Add 0.016129π m and 7.1120183π m

The result can be shown in multiple forms

Exact Form

Area = 7.1281473π m

∴ Surface Area of Cone 5 in by 56 m is 7.1281473π in2

Decimal Form

22.3823825 m2

∴ Surface Area of Cylinder 5 in by 56 m is 22.3823825 in2