Area of an Irregular Quadrilateral Calculator
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Area of an Irregular Quadrilateral diagonal (e) = 27 cm, diagonal(f) = 22 cm and degrees = 2.4 is 401.2251292 cm2
Area of an Irregular Quadrilateral diagonal (e) = 27 cm, diagonal(f) = 22 cm and degrees = 2.4 is 401.2251292 cm2
Area of an Irregular Quadrilateral diagonal (e) = 27 cm, diagonal(f) = 22 cm and degrees = 2.4 in other units
| Value | unit |
|---|---|
| 0.0040123 | km² |
| 0.0024931 | mi² |
| 4.0122513 | m² |
| 13.1635541 | ft² |
| 157.9626493 | in² |
| 4.3878514 | yd² |
| 401.2251292 | cm² |
| 4012.251292 | mm² |
Steps:
Given that Irregular Quadrilateral diagonal (e) = 27 cm, diagonal(f) = 22 cm and radians = 2.4
We know that, Area = e * f * sin(α)
Put the values of e, f and α in above Area Formula
A = 27 * 22 * sin(2.4)
Simplify the above equation
A = 401.2251292 cm²
∴ Area of an Irregular Quadrilateral diagonal (e) = 27 cm, diagonal(f) = 22 cm and degrees = 2.4 is 401.2251292 cm²